3y^4-19y^2-40=0

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Solution for 3y^4-19y^2-40=0 equation:


Simplifying
3y4 + -19y2 + -40 = 0

Reorder the terms:
-40 + -19y2 + 3y4 = 0

Solving
-40 + -19y2 + 3y4 = 0

Solving for variable 'y'.

Factor a trinomial.
(-5 + -3y2)(8 + -1y2) = 0

Subproblem 1

Set the factor '(-5 + -3y2)' equal to zero and attempt to solve: Simplifying -5 + -3y2 = 0 Solving -5 + -3y2 = 0 Move all terms containing y to the left, all other terms to the right. Add '5' to each side of the equation. -5 + 5 + -3y2 = 0 + 5 Combine like terms: -5 + 5 = 0 0 + -3y2 = 0 + 5 -3y2 = 0 + 5 Combine like terms: 0 + 5 = 5 -3y2 = 5 Divide each side by '-3'. y2 = -1.666666667 Simplifying y2 = -1.666666667 The solution to this equation could not be determined. This subproblem is being ignored because a solution could not be determined.

Subproblem 2

Set the factor '(8 + -1y2)' equal to zero and attempt to solve: Simplifying 8 + -1y2 = 0 Solving 8 + -1y2 = 0 Move all terms containing y to the left, all other terms to the right. Add '-8' to each side of the equation. 8 + -8 + -1y2 = 0 + -8 Combine like terms: 8 + -8 = 0 0 + -1y2 = 0 + -8 -1y2 = 0 + -8 Combine like terms: 0 + -8 = -8 -1y2 = -8 Divide each side by '-1'. y2 = 8 Simplifying y2 = 8 Take the square root of each side: y = {-2.828427125, 2.828427125}

Solution

y = {-2.828427125, 2.828427125}

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